There is something I don't understand about this topic. If we rearrange the formula "F= q x E" to find E (i.e. E= F/q), it shows that E (Electric field strength) and q (charge) have an inversely proportional relationship to one another. Which means that if we increase charge, E should decrease.

This video is stating the opposite isn't it? That if we increase charge, we also increase the electric field strength?

Mr Anderson I have a doubt In JJ Thomson experiment whether the deflection is directly proportional to electric field intensity or not? Please explain @Bozeman_science @Anderson

Hi Paul Andersen or anyone that knows the answer,

What software do you use for your presentations? I tried looking around but couldn't find any detail about it.

Thanks!

Your videos are so interesting! Thankyou 🙂

Thank you!!! 🙂

Thanks 🙂

Thank you for the interesting videos!

There is something I don't understand about this topic. If we rearrange the formula "F= q x E" to find E (i.e. E= F/q), it shows that E (Electric field strength) and q (charge) have an inversely proportional relationship to one another. Which means that if we increase charge, E should decrease.

This video is stating the opposite isn't it? That if we increase charge, we also increase the electric field strength?

much much helpful..thanks

can u plz tell me that in millikan's oil drop method

By changimg the strength of electic field how the charge on each droplet was different

Nicely e explained

Very helpful. Thank you professor Anderson.

thank you Mr Anderson

Bozeman > Kahn. Quick and to the point, thank you.

Mr Anderson I have a doubt In JJ Thomson experiment whether the deflection is directly proportional to electric field intensity or not?

Please explain @Bozeman_science @Anderson

It helped clear my concept thankyou!

midnight revision lifesaver

Is a field of 70 volts per meter abnormally high?