sir. since from engineering till now (4 years) i have never understood this concept. u made me understand within 20 mins. guru ji. u r great… u r my som guru.

very very thank full to u sir for giveing such a brief and easy lecture on SOM i got a hope of upstanding in this subject thank u is small word for you sir

thank u sir for this problem it would be very help ful for my exam sir please make more videos on design of gears and design of engine parts related to vtu univercity

Sir this is similar to superposition principle . But I have a doubt in superposition principle that is"y that principle is not applicable for larger deformation s yy . That is in the starting only we assume that deformation on that body is small . Can u pls explain me how the text or by sending any link of the vedio . Pls reply me

Sir you are great . Once this problems were very here for me to understand but now I am able to understand this after seeing this video. Thank you very much for help us Sir🙏🏻🙏🏻

Thanks you so much Sirji for your great explaination, and thanks for the making this video I understand all the problems of analysis of bars of varying sections..😘

The following results were obtained in a tensile test on a mild steel specimen of original diameter 20 mm and gauge length 40 mm = 80 kN Load at limit of proportionality Extension at 80 kN load Load at yield point Maximum load 0.048 mm -85 kN -150 kN When the two parts were fitted together after being broken, the length between gauge length was found to be 55.6 mm and the diameter at the neck was 15.8 mm. Calculate Young's modulus, yield stress, ultimate tensile stress, percentage elongation and percentage reduction in area. IA ns. 213 kN/rn m2; 270 N/mm, 478 N/mm. ; 39%, 38%) what is the solution steps?

upload cam profile problems based topics sir and mohar cricle graphics methods topic

please keep up the good work sir.. such a quality teaching

The teacher's explanation quality is outstanding..

Thank you so much!! your explanation is great!

i'm having my finals soon and that helped me !!

thanks for your explanation.

thank u sir

sir plz make video on governor WHICH is TOPIC OF kanematic of machine…

sir. since from engineering till now (4 years) i have never understood this concept. u made me understand within 20 mins. guru ji. u r great… u r my som guru.

Great work Sir well prepared for tomorrow's test thanks to you….

Great Help! you've earned a subscribe

sir, you are great. Thank you for these videos

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very very thank full to u sir for giveing such a brief and easy lecture on SOM i got a hope of upstanding in this subject thank u is small word for you sir

dear sir some videos are showing like private video and they are not opening please solve this problem

very time consuming lectures

super video.I nicely clarified my doughts .Thank you keeda.

thank u sir for this problem it would be very help ful for my exam sir please make more videos on design of gears and design of engine parts related to vtu univercity

Sir, your way of explaining is superb. Do you have any other video for a problem with a member fixed at rigid plates at both end?

mstttttt maja aa gya sirr

thanks sir

sir plz make video on general heat conduction equation(cartesian coordinate) which is topic of heat transfer

and all the videos related to heat transfer (Mechanical 5th sem)

Good

sir isko hamara sir nehi accept karti he, please sir clarifay me why this happen basically principle if superposition

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please sir apka no meriko chahiye

thank you sir

sir send your Email id so i can send the problem

Thank u sir .aapke vdo se som ka concept bahut easy ho gya

please support my youtube channel https://youtu.be/I77E5RkzBd4

Sir this is similar to superposition principle . But I have a doubt in superposition principle that is"y that principle is not applicable for larger deformation s yy . That is in the starting only we assume that deformation on that body is small . Can u pls explain me how the text or by sending any link of the vedio . Pls reply me

sir u very good job do it …slute u…and thnk u so much sir …

thanks alot sir

a big respect to you sir I don't know how you makes complicated things like ABCD. love you sir # RESPECT

I still dont understand how you resolved forces in the middle segment

Great explanation

Awesome explanation sir it make us easy to understand

U concept ddnt clear enough

Wish had a teacher like you in our college

while taking na elongation of the first section, wouldn't the 10kN forces cancel out each other?

Sir kabhi esa ho sakta hain ki 1 bar ka elongation ho aur dusre ko length decrease ho

The middle section calculation is wrong it is compressive stress not tensile…

Can I get pdf file of stress stain notes

Email me to [email protected]

Sir pls give your link so that I can get new video of yours

Sir you are great . Once this problems were very here for me to understand but now I am able to understand this after seeing this video. Thank you very much for help us Sir🙏🏻🙏🏻

Sir deflection by conjugate beam method pr v vedio bnao

Sir when lengths is not given so can we assume the length

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Thankyou

Thanks you so much Sirji for your great explaination, and thanks for the making this video I understand all the problems of analysis of bars of varying sections..😘

Sir, Aapne last Mai p + 20 Kese liya

Very very thanks sir but give lecture in hindi please

The following results were obtained in a tensile test on a mild steel specimen of original diameter 20 mm and gauge length 40 mm = 80 kN Load at limit of proportionality Extension at 80 kN load Load at yield point Maximum load 0.048 mm -85 kN -150 kN When the two parts were fitted together after being broken, the length between gauge length was found to be 55.6 mm and the diameter at the neck was 15.8 mm. Calculate Young's modulus, yield stress, ultimate tensile stress, percentage elongation and percentage reduction in area. IA ns. 213 kN/rn m2; 270 N/mm, 478 N/mm. ; 39%, 38%) what is the solution steps?