Understanding Control Systems, Part 4: Simulating Disturbance Rejection in Simulink


Hello! in this video, I’m going to simulate a car
maintaining a constant speed. Ok, not like that. I’m going to use Simulink,
which is a block diagram environment that lets us model our physical system visually,
and then simulate it. Here, you see a screenshot taken from the
previous video where we used the car example. We want to control the speed of our car, keeping
it steady at 20 m/s. First, I want to look at the open-loop system
response. I’ll start with simulating this part which consists
of the actuator and the plant. In order to model a system in Simulink, you use
blocks from Simulink Library Browser. There are different add-ons. Here, I’m going to use a custom library that I’ve
previously created and imported to this library
browser. In my custom library, I have preconfigured
blocks. If you want to look at what’s inside these
subsystems, this demo model is available
online. Download it by clicking the link below this video. Using blocks from this library, I create the open-
loop system. I’ll start with an input of pi/18 radians. This corresponds to 10⁰. To see how my speed changes when I press
down the gas pedal by 10⁰, I’ll hit the play button and simulate this system. Here is my input of 10⁰ or pi/18 radians. And the speed converges to, if I zoom in here,
approximately 6.6 m/s, but my goal was to get to 20 m/s, which means
I need to press down further on the gas pedal. For an input of 10⁰, I get 6.6 m/s. I know that this is a linear system; therefore, to
get to three times the current speed of 6.6 m/s, I need to triple the input. I increase the angle from 10⁰ to 30⁰ or pi/6 in
radians and re-simulate my model. This is my input of 30⁰. As expected, my speed converges to the
desired speed. Now I have tuned this open-loop system to
make the car go 20 m/s, which is what we
wanted. Until now, I’ve been assuming that the car is
driving on a flat road. But what if the car climbs a hill? Will it still be able to maintain the correct
speed? To answer this question, I will simulate the car
going uphill. When climbing the hill, there’s an additional
disturbance force acting on the car. To address that, I’ll add this disturbance to my
model. I’ve preconfigured this disturbance block such
that the disturbance acts at 200 seconds. So, to see the effect of the disturbance in my
simulation I’m extending simulation time to 400
seconds. If I simulate my system now, this is my
disturbance which is constant and acts at 200
seconds and I see that my speed drops significantly
while going uphill. This means the open-loop system fails if there’s
a disturbance acting on the system. Are you with me so far? Don’t go anywhere yet because we came to the
most exciting part where we’re going to close
the loop and then the magic will happen. The simulation showed that open-loop fails in
the presence of unpredicted disturbances. However, we’re all set, because we already
know from the previous videos that the solution
to this problem is to use feedback control. So, that’s what I’m going to do next. I’ll close the loop using the pre-configured
blocks from my custom library and simulate the closed-loop system. Noise enters the system through measurement. For realistic simulation results, I make sure to
add noise to my model. I set the desired output to 20 m/s as this is the
speed that we want to maintain. Once the feedback control system is ready, I hit
the play button to simulate it. As opposed to open-loop control, we see that
feedback control compensates for the
disturbance. To gain insight into how it deals with the
disturbance, let’s take a look at the error and the pedal
position signals. The reason that open-loop control can’t
compensate for the disturbance is that it only provides a static input to the
actuator. But in the presence of a disturbance, like if we’re going uphill, we need to press down
further on the gas pedal. This means we need to change the input to the
actuator dynamically instead of keeping it
constant. And this is exactly what feedback control does. The controller sees that the error is growing
when there’s disturbance. And it increases the signal to the actuator,
which in turn increases the engine force and the
speed of the car. And in this way, the error is pulled back to zero. I hope you learned little more about how you can
simulate a control system in Simulink. In the next video, using Simulink we’ll simulate
robustness to system variations.

16 Replies to “Understanding Control Systems, Part 4: Simulating Disturbance Rejection in Simulink”

  1. Download the model used in this video here: https://www.mathworks.com/matlabcentral/fileexchange/69001-simulating-disturbance-rejection-in-simulink

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